From 4de1b39b4f428200241f726fe32d77a1f6bcc30a Mon Sep 17 00:00:00 2001
From: Yorik van Havre <yorik@uncreated.net>
Date: Mon, 1 Aug 2016 13:17:47 -0300
Subject: [PATCH] Spreadsheet: Made SheetPython inherit python object from
 Sheet

---
 src/Mod/Spreadsheet/App/Sheet.cpp | 8 ++++++++
 1 file changed, 8 insertions(+)

diff --git a/src/Mod/Spreadsheet/App/Sheet.cpp b/src/Mod/Spreadsheet/App/Sheet.cpp
index d7e2e8192..927785d9c 100644
--- a/src/Mod/Spreadsheet/App/Sheet.cpp
+++ b/src/Mod/Spreadsheet/App/Sheet.cpp
@@ -33,6 +33,7 @@
 #include <App/Application.h>
 #include <App/Document.h>
 #include <App/DynamicProperty.h>
+#include <App/FeaturePythonPyImp.h>
 #include <Base/Exception.h>
 #include <Base/Placement.h>
 #include <Base/Reader.h>
@@ -1345,6 +1346,13 @@ PROPERTY_SOURCE_TEMPLATE(Spreadsheet::SheetPython, Spreadsheet::Sheet)
 template<> const char* Spreadsheet::SheetPython::getViewProviderName(void) const {
     return "SpreadsheetGui::ViewProviderSheet";
 }
+template<> PyObject* Spreadsheet::SheetPython::getPyObject(void) {
+    if (PythonObject.is(Py::_None())) {
+        // ref counter is set to 1
+        PythonObject = Py::Object(new FeaturePythonPyT<Spreadsheet::SheetPy>(this),true);
+    }
+    return Py::new_reference_to(PythonObject);
+}
 /// @endcond
 
 // explicit template instantiation