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Update function to be clear

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Update function to be clear and without hardcoded payload
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Stanislav Mikhaylov 2018-10-09 11:10:27 +03:00 committed by GitHub
parent 9f8c93dc04
commit a4276677b8
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1 changed files with 12 additions and 10 deletions
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README.md
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@ -201,31 +201,33 @@ encryptDecryptFunction()
Encrypt with multiple public keys:
```js
const pubkey1 = `-----BEGIN PGP PUBLIC KEY BLOCK-----
const pubkeys = [`-----BEGIN PGP PUBLIC KEY BLOCK-----
...
-----END PGP PUBLIC KEY BLOCK-----`
const pubkey2 = `-----BEGIN PGP PUBLIC KEY BLOCK-----
-----END PGP PUBLIC KEY BLOCK-----`,
`-----BEGIN PGP PUBLIC KEY BLOCK-----
...
-----END PGP PUBLIC KEY BLOCK-----`
const privkey = `-----BEGIN PGP PRIVATE KEY BLOCK-----
...
-----END PGP PRIVATE KEY BLOCK-----` //encrypted private key
const passphrase = `yourPassphrase` //what the privKey is encrypted with
const message = 'Hello, World!' // input as Message object
const encryptWithMultiplePublicKeys = async() => {
async encryptWithMultiplePublicKeys(pubkeys, privkey, passphrase, message) {
const privKeyObj = (await openpgp.key.readArmored(privkey)).keys[0]
await privKeyObj.decrypt(passphrase)
pubkeys = pubkeys.map(async (key) => {
return (await openpgp.key.readArmored(key)).keys[0]
});
const options = {
message: openpgp.message.fromText('Hello, World!'), // input as Message object
publicKeys: [ // for encryption
openpgp.key.readArmored(pubkey1).keys[0],
openpgp.key.readArmored(pubkey2).keys[0]
],
message: openpgp.message.fromText(message),
publicKeys: pubkeys, // for encryption
privateKeys: [privKeyObj] // for signing (optional)
}
openpgp.encrypt(options).then(ciphertext => {
return openpgp.encrypt(options).then(ciphertext => {
encrypted = ciphertext.data // '-----BEGIN PGP MESSAGE ... END PGP MESSAGE-----'
return encrypted
})