racket/collects/srfi/1/delete.rkt
2011-07-02 10:37:53 -04:00

70 lines
2.2 KiB
Racket

;;;
;;; <delete.rkt> ---- List deletion functions
;;; Time-stamp: <02/03/01 07:26:12 noel>
;;;
;;; Copyright (C) 2002 by Noel Welsh.
;;;
;;; This file is part of SRFI-1.
;;; This SRFI-1 implementation is distributed under the same terms as
;;; Racket.
;;; Author: Noel Welsh <noelwelsh@yahoo.com>
;; Commentary:
;; Based on the reference implementation by Olin Shiver and hence:
;; Copyright (c) 1998, 1999 by Olin Shivers. You may do as you please with
;; this code as long as you do not remove this copyright notice or
;; hold me liable for its use. Please send bug reports to shivers@ai.mit.edu.
;; -Olin
;; Olin Shivers verified that he is fine with redistributing this code
;; under the LGPL. (Verified personally by Eli Barzilay.)
#lang scheme/base
(require srfi/optional "predicate.rkt")
(provide delete (rename-out [delete delete!])
delete-duplicates (rename-out [delete-duplicates delete-duplicates!]))
(define (delete x lis [= equal?])
(filter (lambda (y) (not (= x y))) lis))
#; ; lists are immutable
(define delete! (x lis [= equal?])
(filter! (lambda (y) (not (= x y))) lis))
;; right-duplicate deletion
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
;; delete-duplicates delete-duplicates!
;;
;; Beware -- these are N^2 algorithms. To efficiently remove duplicates
;; in long lists, sort the list to bring duplicates together, then use a
;; linear-time algorithm to kill the dups. Or use an algorithm based on
;; element-marking. The former gives you O(n lg n), the latter is linear.
(define (delete-duplicates lis [elt= equal?])
(check-arg procedure? elt= 'delete-duplicates)
(let recur ((lis lis))
(if (null-list? lis) lis
(let* ((x (car lis))
(tail (cdr lis))
(new-tail (recur (delete x tail elt=))))
(if (eq? tail new-tail) lis (cons x new-tail))))))
#; ; lists are immutable
(define (delete-duplicates! lis [elt= equal?])
(check-arg procedure? elt= 'delete-duplicates!)
(let recur ((lis lis))
(if (null-list? lis) lis
(let* ((x (car lis))
(tail (cdr lis))
(new-tail (recur (delete! x tail elt=))))
(if (eq? tail new-tail) lis (cons x new-tail))))))
;;; delete.rkt ends here