![]() revision). So what we'll get here is the following: Dotted + Dotted = Dotted (from the first case) Dotted + x = x (since x refers to a free use of the dotted var) x + Dotted = x (same) I think this is correct. |
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lang | ||
private | ||
info.ss | ||
main.ss | ||
minimal.ss | ||
typed-reader.ss | ||
typed-scheme.scrbl | ||
typed-scheme.ss |