racket/collects/tests/eopl/chapter3/letrec-lang/tests.rkt
David Van Horn 7491e172ea EOPL test suite re-written in Racket-based #lang eopl and rackunit
The eopl language is now racket-based rather than mzscheme-based.  This
test-suite, which was originally distributed on the book's web-site has
been re-written in the new language.  Changes include dropping all
drscheme-init.scm and top.scm files.  Remaining files were renamed to
use the .rkt extension and edited to use the #lang syntax (instead of
modulue).  Require and provide forms were changed to reflect racket's
syntax instead of mzscheme's (eg, only-in vs. only).  Several
occurrences of one-armed ifs were changed to use when and unless.  All
tests have been run successfully.
2012-02-24 14:46:18 -05:00

129 lines
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#lang eopl
(require tests/eopl/private/utils)
(require "data-structures.rkt") ; for expval constructors
(require "lang.rkt") ; for scan&parse
(require "interp.rkt") ; for value-of-program
;; run : String -> ExpVal
(define run
(lambda (string)
(value-of-program (scan&parse string))))
(define equal-answer?
(lambda (ans correct-ans)
(equal? ans (sloppy->expval correct-ans))))
(define sloppy->expval
(lambda (sloppy-val)
(cond
((number? sloppy-val) (num-val sloppy-val))
((boolean? sloppy-val) (bool-val sloppy-val))
(else
(eopl:error 'sloppy->expval
"Can't convert sloppy value to expval: ~s"
sloppy-val)))))
(define-syntax-rule (check-run (name str res) ...)
(begin
(cond [(eqv? 'res 'error)
(check-exn always? (lambda () (run str)))]
[else
(check equal-answer? (run str) 'res (symbol->string 'name))])
...))
;;;;;;;;;;;;;;;; tests ;;;;;;;;;;;;;;;;
(check-run
;; simple arithmetic
(positive-const "11" 11)
(negative-const "-33" -33)
(simple-arith-1 "-(44,33)" 11)
;; nested arithmetic
(nested-arith-left "-(-(44,33),22)" -11)
(nested-arith-right "-(55, -(22,11))" 44)
;; simple variables
(test-var-1 "x" 10)
(test-var-2 "-(x,1)" 9)
(test-var-3 "-(1,x)" -9)
;; simple unbound variables
(test-unbound-var-1 "foo" error)
(test-unbound-var-2 "-(x,foo)" error)
;; simple conditionals
(if-true "if zero?(0) then 3 else 4" 3)
(if-false "if zero?(1) then 3 else 4" 4)
;; test dynamic typechecking
(no-bool-to-diff-1 "-(zero?(0),1)" error)
(no-bool-to-diff-2 "-(1,zero?(0))" error)
(no-int-to-if "if 1 then 2 else 3" error)
;; make sure that the test and both arms get evaluated
;; properly.
(if-eval-test-true "if zero?(-(11,11)) then 3 else 4" 3)
(if-eval-test-false "if zero?(-(11, 12)) then 3 else 4" 4)
;; and make sure the other arm doesn't get evaluated.
(if-eval-test-true-2 "if zero?(-(11, 11)) then 3 else foo" 3)
(if-eval-test-false-2 "if zero?(-(11,12)) then foo else 4" 4)
;; simple let
(simple-let-1 "let x = 3 in x" 3)
;; make sure the body and rhs get evaluated
(eval-let-body "let x = 3 in -(x,1)" 2)
(eval-let-rhs "let x = -(4,1) in -(x,1)" 2)
;; check nested let and shadowing
(simple-nested-let "let x = 3 in let y = 4 in -(x,y)" -1)
(check-shadowing-in-body "let x = 3 in let x = 4 in x" 4)
(check-shadowing-in-rhs "let x = 3 in let x = -(x,1) in x" 2)
;; simple applications
(apply-proc-in-rator-pos "(proc(x) -(x,1) 30)" 29)
(apply-simple-proc "let f = proc (x) -(x,1) in (f 30)" 29)
(let-to-proc-1 "(proc(f)(f 30) proc(x)-(x,1))" 29)
(nested-procs "((proc (x) proc (y) -(x,y) 5) 6)" -1)
(nested-procs2 "let f = proc(x) proc (y) -(x,y) in ((f -(10,5)) 6)"
-1)
(y-combinator-1 "
let fix = proc (f)
let d = proc (x) proc (z) ((f (x x)) z)
in proc (n) ((f (d d)) n)
in let
t4m = proc (f) proc(x) if zero?(x) then 0 else -((f -(x,1)),-4)
in let times4 = (fix t4m)
in (times4 3)" 12)
;; simple letrecs
(simple-letrec-1 "letrec f(x) = -(x,1) in (f 33)" 32)
(simple-letrec-2
"letrec f(x) = if zero?(x) then 0 else -((f -(x,1)), -2) in (f 4)"
8)
(simple-letrec-3
"let m = -5
in letrec f(x) = if zero?(x) then 0 else -((f -(x,1)), m) in (f 4)"
20)
;; alas, no multiplication in this language. Exercise: define
;; multiplication as a letrec and then use it to define factorial.
;; (fact-of-6 "letrec
;; fact(x) = if zero?(x) then 1 else *(x, (fact sub1(x)))
;; in (fact 6)"
;; 720)
(HO-nested-letrecs
"letrec even(odd) = proc(x) if zero?(x) then 1 else (odd -(x,1))
in letrec odd(x) = if zero?(x) then 0 else ((even odd) -(x,1))
in (odd 13)" 1)
)