383ca01434
Summary: Add some things in to make this more useful to khan-exercises. Notably, make KaTeX.process create and clean up its own .katex node, and rename .mathmathmath -> .katex. Test Plan: Make test, make sure the main page still renders stuff Reviewers: alpert Reviewed By: alpert Differential Revision: http://phabricator.khanacademy.org/D3061
72 lines
1.8 KiB
JavaScript
72 lines
1.8 KiB
JavaScript
var ParseError = require("./ParseError");
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// The main lexer class
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function Lexer(input) {
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this._input = input;
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};
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// The result of a single lex
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function LexResult(type, text, position) {
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this.type = type;
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this.text = text;
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this.position = position;
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}
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// "normal" types of tokens
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var normals = [
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[/^[/|@."`0-9]/, 'textord'],
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[/^[a-zA-Z]/, 'mathord'],
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[/^[*+-]/, 'bin'],
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[/^[=<>]/, 'rel'],
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[/^[,;]/, 'punct'],
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[/^'/, "'"],
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[/^\^/, '^'],
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[/^_/, '_'],
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[/^{/, '{'],
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[/^}/, '}'],
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[/^[(\[]/, 'open'],
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[/^[)\]?!]/, 'close']
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];
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// Build a regex to easily parse the functions
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var anyFunc = /^\\(?:[a-zA-Z]+|.)/;
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// Lex a single token
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Lexer.prototype.lex = function(pos) {
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var input = this._input.slice(pos);
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// Get rid of whitespace
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var whitespace = input.match(/^\s*/)[0];
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pos += whitespace.length;
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input = input.slice(whitespace.length);
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// If there's no more input to parse, return an EOF token
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if (input.length === 0) {
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return new LexResult('EOF', null, pos);
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}
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var match;
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if ((match = input.match(anyFunc))) {
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// If we match one of the tokens, extract the type
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return new LexResult(match[0], match[0], pos + match[0].length);
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} else {
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// Otherwise, we look through the normal token regexes and see if it's
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// one of them.
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for (var i = 0; i < normals.length; i++) {
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var normal = normals[i];
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if ((match = input.match(normal[0]))) {
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// If it is, return it
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return new LexResult(
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normal[1], match[0], pos + match[0].length);
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}
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}
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}
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// We didn't match any of the tokens, so throw an error.
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throw new ParseError("Unexpected character: '" + input[0] +
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"' at position " + pos);
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};
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module.exports = Lexer;
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