Fixes #434 (Type of literal char is not the literal char itself) using solution from Alex Knauth.
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@ -28,7 +28,7 @@
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;; tc-literal: racket-value-syntax [type] -> type
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(define (tc-literal v-stx [expected #f])
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(define-syntax-class exp
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(pattern (~and i (~or :number :str :bytes))
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(pattern (~and i (~or :number :str :bytes :char))
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#:fail-unless expected #f
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#:fail-unless (let ([n (syntax-e #'i)])
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(subtype (-val n) expected #:obj (if (exact-integer? n) (-lexp n) -empty-obj))) #f))
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22
typed-racket-test/succeed/literal-char-gh-issue-434.rkt
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22
typed-racket-test/succeed/literal-char-gh-issue-434.rkt
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@ -0,0 +1,22 @@
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#lang typed/racket
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;; The precise type for chars should be the char itself:
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(ann #\nul #\nul)
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(ann #\a #\a)
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(ann #\b '#\b)
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;; Up-casting as Char should still work:
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(ann #\nul Char)
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(ann #\a Char)
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(ann (ann #\b '#\b) Char)
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;; Check that the inferred type is still implicitly widened to Char by default,
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;; for backwards compatibility (previously, all chars had the type Char):
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;; * Check that when passed as a #:∀ type, the inferred type is Char
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(ann (let #:∀ (C) ([c : C #\a])
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(λ ([x : C]) x))
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(→ Char Char))
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;; * Check that loops which rely on the first iteration having the wider Char
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;; type still work:
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(let loop : Void ([c #\a])
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(if (equal? c #\a)
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(loop #\b)
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(void)))
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