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Spreadsheet: Made SheetPython inherit python object from Sheet

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This commit is contained in:
Yorik van Havre 2016-08-01 13:17:47 -03:00
parent f532e60f30
commit 4de1b39b4f
1 changed files with 8 additions and 0 deletions
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8
src/Mod/Spreadsheet/App/Sheet.cpp
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@ -33,6 +33,7 @@
#include <App/Application.h> #include <App/Application.h>
#include <App/Document.h> #include <App/Document.h>
#include <App/DynamicProperty.h> #include <App/DynamicProperty.h>
#include <App/FeaturePythonPyImp.h>
#include <Base/Exception.h> #include <Base/Exception.h>
#include <Base/Placement.h> #include <Base/Placement.h>
#include <Base/Reader.h> #include <Base/Reader.h>
@ -1345,6 +1346,13 @@ PROPERTY_SOURCE_TEMPLATE(Spreadsheet::SheetPython, Spreadsheet::Sheet)
template<> const char* Spreadsheet::SheetPython::getViewProviderName(void) const { template<> const char* Spreadsheet::SheetPython::getViewProviderName(void) const {
return "SpreadsheetGui::ViewProviderSheet"; return "SpreadsheetGui::ViewProviderSheet";
} }
template<> PyObject* Spreadsheet::SheetPython::getPyObject(void) {
if (PythonObject.is(Py::_None())) {
// ref counter is set to 1
PythonObject = Py::Object(new FeaturePythonPyT<Spreadsheet::SheetPy>(this),true);
}
return Py::new_reference_to(PythonObject);
}
/// @endcond /// @endcond
// explicit template instantiation // explicit template instantiation